Programming Challenges: Interpreter
PC/UVa IDs: 110106/10033, Popularity: B, Success rate: low, Level: 2
Nothing extraordinarily interesting here — typical straight-outta-the-book exercise.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 | #include <iostream> #include <string> #include <sstream> #include <vector> using namespace std; bool decode(int &pc, vector< int > ®, vector< int > &ram) { int inst = ram.at(pc); int c = inst / 100, a = (inst % 100) / 10, b = inst % 10; switch(c) { case 1: return false; break; case 2: reg.at(a) = b; pc++; break; case 3: reg.at(a) += b; reg.at(a) %= 1000; pc++; break; case 4: reg.at(a) *= b; reg.at(a) %= 1000; pc++; break; case 5: reg.at(a) = reg.at(b); pc++; break; case 6: reg.at(a) += reg.at(b); reg.at(a) %= 1000; pc++; break; case 7: reg.at(a) *= reg.at(b); reg.at(a) %= 1000; pc++; break; case 8: reg.at(a) = ram.at(reg.at(b)); pc++; break; case 9: ram.at(reg.at(b)) = reg.at(a); pc++; break; case 0: if(reg.at(b) == 0) { pc++; } else { pc = reg.at(a); } break; } return true; } int main(int argc, char *argv[]) { string dummy; int ncases; cin>>ncases; // ignore two empty lines getline(cin, dummy); getline(cin, dummy); for(int n = 0; n < ncases; n++) { vector< int > reg(10), ram(1000); fill(reg.begin(), reg.end(), 0); fill(ram.begin(), ram.end(), 0); for(int i = 0; i < 1000; i++) { string str; getline(cin, str); if(str == "") { break; } istringstream iss(str); iss>>ram.at(i); } int executed = 1; int pc = 0; while(decode(pc, reg, ram)) { executed++; } if(n > 0) { cout<<endl; } cout<<executed<<endl; } return 0; } |