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July 1, 2008

Programming Challenges: Graphical Editor

Filed under: Blog — krkhan @ 1:31 am

PC/UVa IDs: 110105/10267, Popularity: B, Success rate: low, Level: 1

Few notes:

  • In the problem input, pixels are specified as [column# row#], whereas two-dimensional vectors (or arrays) are referenced using [row# column#] format.
  • The program would be doomed to infinite recursion if the condition on line #51 is omitted.
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#include <iostream>
#include <string>
#include <sstream>
#include <vector>
#include <iterator>
 
using namespace std;
 
typedef vector< vector< char > > twod_vector;
 
ostream& operator<<(ostream &out, const twod_vector &v)
{
	twod_vector::const_iterator p;
 
	for(p = v.begin(); p < v.end(); p++) {
		copy((*p).begin(), (*p).end(),
				ostream_iterator< char >(cout, ""));
		cout<<endl;
	}
 
	return out;
}
 
void reset(twod_vector &image)
{
	twod_vector::iterator p;
 
	for(p = image.begin(); p < image.end(); p++) {
		fill((*p).begin(), (*p).end(), 'O');
	}
}
 
void set_pixel(twod_vector &image, int x, int y, char c)
{
	image.at(y).at(x) = c;
}
 
void fill_rect(twod_vector &image,
		int x1, int y1, int x2, int y2, char c)
{
	for(int i = y1; i <= y2; i++) {
		for(int j = x1; j <= x2; j++) {
			image.at(i).at(j) = c;
		}
	}
}
 
void fill_region(twod_vector &image, int x, int y,
		char old_color, char new_color)
{
	if(old_color == new_color) {
		return;
	}
 
	image.at(y).at(x) = new_color;
 
	if(x > 0) {
		if(image.at(y).at(x - 1) == old_color) {
			fill_region(image, x - 1, y,
					old_color, new_color);
		}
	}
 
	if(x < static_cast<int>(image.at(y).size()) - 1) {
		if(image.at(y).at(x + 1) == old_color) {
			fill_region(image, x + 1, y,
					old_color, new_color);
		}
	}
 
	if(y > 0) {
		if(image.at(y - 1).at(x) == old_color) {
			fill_region(image, x, y - 1,
					old_color, new_color);
		}
	}
 
	if(y < static_cast<int>(image.size()) - 1) {
		if(image.at(y + 1).at(x) == old_color) {
			fill_region(image, x, y + 1,
					old_color, new_color);
		}
	}
}
 
void swap(int &x, int &y)
{
	int tmp = x;
	x = y;
	y = tmp;
}
 
int main(int argc, char *argv[])
{
	twod_vector image;
	string line;
 
	getline(cin, line);
	while(line[0] != 'X') {
		istringstream iss(line);
		int m, n, x, y, x1, x2, y1, y2;
		char command, c, file_name[13];
		twod_vector::iterator p;
 
		iss>>command;
		switch(command) {
		case 'I':
			iss>>m>>n;
 
			image.clear();
			image.resize(n);
			for(p = image.begin(); p < image.end(); p++) {
				(*p).resize(m);
			}
 
			reset(image);
 
			break;
		case 'C':
			reset(image);
 
			break;
		case 'L':
			iss>>x>>y>>c;
			x--;
			y--;
 
			set_pixel(image, x, y, c);
 
			break;
		case 'V':
			iss>>x>>y1>>y2>>c;
			x--;
			y1--;
			y2--;
 
			if(y1 > y2) {
				swap(y1, y2);
			}
 
			fill_rect(image, x, y1, x, y2, c);
 
			break;
		case 'H':
			iss>>x1>>x2>>y>>c;
			x1--;
			x2--;
			y--;
 
			if(x1 > x2) {
				swap(x1, x2);
			}
 
			fill_rect(image, x1, y, x2, y, c);
 
			break;
		case 'K':
			iss>>x1>>y1>>x2>>y2>>c;
			x1--;
			y1--;
			x2--;
			y2--;
 
			if(x1 > x2) {
				swap(x1, x2);
			}
			if(y1 > y2) {
				swap(y1, y2);
			}
 
			fill_rect(image, x1, y1, x2, y2, c);
 
			break;
		case 'F':
			iss>>x>>y>>c;
			x--;
			y--;
 
			fill_region(image, x, y,
					image.at(y).at(x), c);
 
			break;
		case 'S':
			iss.ignore();
			iss.getline(file_name, 13);
 
			cout<<file_name<<endl;
			cout<<image;
 
			break;
		}
 
		getline(cin, line);
	}
 
	return 0;
}
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June 30, 2008

Programming Challenges: LCD Display

Filed under: Blog — krkhan @ 8:35 am

PC/UVa IDs: 110104/706, Popularity: A, Success rate: average, Level: 1

Two-dimensional vectors again, with an array of function pointers to construct the digits’ appearance.

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#include <iostream>
#include <cmath>
#include <string>
#include <sstream>
#include <vector>
#include <iterator>
#include <algorithm>
 
#define PRINTCHARV	'|'
#define PRINTCHARH	'-'
#define FILLCHAR	' '
 
using namespace std;
 
vector< char > row_fill(int cols, char c1, char c2, char c3)
{
	const int firstcol = 0, lastcol = cols - 1;
	vector< char > v(cols);
 
	v.at(firstcol) = c1;
	for(int i = firstcol + 1; i <= lastcol - 1; i++) {
		v.at(i) = c2;
	}
	v.at(lastcol) = c3;
 
	return v;
}
 
vector< char > row_mid(int cols)
{
	return row_fill(cols, FILLCHAR, PRINTCHARH, FILLCHAR);
}
 
vector< char > row_left_side(int cols)
{
	return row_fill(cols, PRINTCHARV, FILLCHAR, FILLCHAR);
}
 
vector< char > row_right_side(int cols)
{
	return row_fill(cols, FILLCHAR, FILLCHAR, PRINTCHARV);
}
 
vector< char > row_both_sides(int cols)
{
	return row_fill(cols, PRINTCHARV, FILLCHAR, PRINTCHARV);
}
 
vector< char > row_empty(int cols)
{
	return row_fill(cols, FILLCHAR, FILLCHAR, FILLCHAR);
}
 
vector< vector< char > > col_empty(int s)
{
	const int rows = 2 * s + 3;
	vector< vector< char > > v(rows);
 
	for(int i = 0; i < rows; i++) {
		v.at(i).push_back(FILLCHAR);
	}
 
	return v;
}
 
vector< vector< char > > lcd(int s, int n)
{
	const int rows = 2 * s + 3;
	const int cols = s + 2;
	const int firstrow = 0,
		midrow = static_cast<int>(floor(rows / 2.00)),
		lastrow = rows - 1;
	vector< vector< char > > v(rows);
	vector< char > (*table[10][5])(int) = {
	// 0
	{row_mid, row_both_sides, row_empty, row_both_sides, row_mid},
	// 1
	{row_empty, row_right_side, row_empty, row_right_side, row_empty},
	// 2
	{row_mid, row_right_side, row_mid, row_left_side, row_mid},
	// 3
	{row_mid, row_right_side, row_mid, row_right_side, row_mid},
	// 4
	{row_empty, row_both_sides, row_mid, row_right_side, row_empty},
	// 5
	{row_mid, row_left_side, row_mid, row_right_side, row_mid},
	// 6
	{row_mid, row_left_side, row_mid, row_both_sides, row_mid},
	// 7
	{row_mid, row_right_side, row_empty, row_right_side, row_empty},
	// 8
	{row_mid, row_both_sides, row_mid, row_both_sides, row_mid},
	// 9
	{row_mid, row_both_sides, row_mid, row_right_side, row_mid}
	};
 
	for(int i = 0; i < rows; i++) {
		v.at(i).resize(cols);
	}
 
	v.at(firstrow) = (*table[n][0])(cols);
 
	for(int i = firstrow + 1; i <= midrow - 1; i++) {
		v.at(i) = (*table[n][1])(cols);
	}
 
	v.at(midrow) = (*table[n][2])(cols);
 
	for(int i = midrow + 1; i <= lastrow - 1; i++) {
		v.at(i) = (*table[n][3])(cols);
	}
 
	v.at(lastrow) = (*table[n][4])(cols);
 
	return v;
}
 
ostream& operator<<(ostream &out, const vector< vector< char > > &v)
{
 
	vector< vector< char > >::const_iterator p;
 
	for(p = v.begin(); p < v.end(); p++) {
		copy((*p).begin(), (*p).end(),
			ostream_iterator< char >(cout, ""));
		cout<<endl;
	}
 
	return out;
}
 
int main(int argc, char *argv[])
{
	int s = -1, n = -1;
 
	cin>>s>>n;
	while(s != 0) {
		const int rows = 2 * s + 3;
 
		ostringstream oss;
		oss<<n;
		istringstream iss(oss.str());
 
		vector< vector< char > >v(rows);
		char c;
		int counter = 0;
		while(iss>>c) {
			int digit = c - '0';
			vector< vector< char > > vd = lcd(s, digit);
 
 
			if(counter > 0) {
				vector< vector< char > > ve
					= col_empty(s);
 
				for(int i = 0; i < rows; i++) {
					copy(ve.at(i).begin(),
						ve.at(i).end(),
						back_inserter(v.at(i)));
				}
			}
 
			for(int i = 0; i < rows; i++) {
				copy(vd.at(i).begin(),
					vd.at(i).end(),
					back_inserter(v.at(i)));
			}
 
			counter++;
		}
		cout<<v<<endl;
 
		cin>>s>>n;
	}
 
	return 0;
}
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