Programming Challenges: LCD Display
PC/UVa IDs: 110104/706, Popularity: A, Success rate: average, Level: 1
Two-dimensional vectors again, with an array of function pointers to construct the digits’ appearance.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 | #include <iostream> #include <cmath> #include <string> #include <sstream> #include <vector> #include <iterator> #include <algorithm> #define PRINTCHARV '|' #define PRINTCHARH '-' #define FILLCHAR ' ' using namespace std; vector< char > row_fill(int cols, char c1, char c2, char c3) { const int firstcol = 0, lastcol = cols - 1; vector< char > v(cols); v.at(firstcol) = c1; for(int i = firstcol + 1; i <= lastcol - 1; i++) { v.at(i) = c2; } v.at(lastcol) = c3; return v; } vector< char > row_mid(int cols) { return row_fill(cols, FILLCHAR, PRINTCHARH, FILLCHAR); } vector< char > row_left_side(int cols) { return row_fill(cols, PRINTCHARV, FILLCHAR, FILLCHAR); } vector< char > row_right_side(int cols) { return row_fill(cols, FILLCHAR, FILLCHAR, PRINTCHARV); } vector< char > row_both_sides(int cols) { return row_fill(cols, PRINTCHARV, FILLCHAR, PRINTCHARV); } vector< char > row_empty(int cols) { return row_fill(cols, FILLCHAR, FILLCHAR, FILLCHAR); } vector< vector< char > > col_empty(int s) { const int rows = 2 * s + 3; vector< vector< char > > v(rows); for(int i = 0; i < rows; i++) { v.at(i).push_back(FILLCHAR); } return v; } vector< vector< char > > lcd(int s, int n) { const int rows = 2 * s + 3; const int cols = s + 2; const int firstrow = 0, midrow = static_cast<int>(floor(rows / 2.00)), lastrow = rows - 1; vector< vector< char > > v(rows); vector< char > (*table[10][5])(int) = { // 0 {row_mid, row_both_sides, row_empty, row_both_sides, row_mid}, // 1 {row_empty, row_right_side, row_empty, row_right_side, row_empty}, // 2 {row_mid, row_right_side, row_mid, row_left_side, row_mid}, // 3 {row_mid, row_right_side, row_mid, row_right_side, row_mid}, // 4 {row_empty, row_both_sides, row_mid, row_right_side, row_empty}, // 5 {row_mid, row_left_side, row_mid, row_right_side, row_mid}, // 6 {row_mid, row_left_side, row_mid, row_both_sides, row_mid}, // 7 {row_mid, row_right_side, row_empty, row_right_side, row_empty}, // 8 {row_mid, row_both_sides, row_mid, row_both_sides, row_mid}, // 9 {row_mid, row_both_sides, row_mid, row_right_side, row_mid} }; for(int i = 0; i < rows; i++) { v.at(i).resize(cols); } v.at(firstrow) = (*table[n][0])(cols); for(int i = firstrow + 1; i <= midrow - 1; i++) { v.at(i) = (*table[n][1])(cols); } v.at(midrow) = (*table[n][2])(cols); for(int i = midrow + 1; i <= lastrow - 1; i++) { v.at(i) = (*table[n][3])(cols); } v.at(lastrow) = (*table[n][4])(cols); return v; } ostream& operator<<(ostream &out, const vector< vector< char > > &v) { vector< vector< char > >::const_iterator p; for(p = v.begin(); p < v.end(); p++) { copy((*p).begin(), (*p).end(), ostream_iterator< char >(cout, "")); cout<<endl; } return out; } int main(int argc, char *argv[]) { int s = -1, n = -1; cin>>s>>n; while(s != 0) { const int rows = 2 * s + 3; ostringstream oss; oss<<n; istringstream iss(oss.str()); vector< vector< char > >v(rows); char c; int counter = 0; while(iss>>c) { int digit = c - '0'; vector< vector< char > > vd = lcd(s, digit); if(counter > 0) { vector< vector< char > > ve = col_empty(s); for(int i = 0; i < rows; i++) { copy(ve.at(i).begin(), ve.at(i).end(), back_inserter(v.at(i))); } } for(int i = 0; i < rows; i++) { copy(vd.at(i).begin(), vd.at(i).end(), back_inserter(v.at(i))); } counter++; } cout<<v<<endl; cin>>s>>n; } return 0; } |
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